Questions?

I just want you to print the names of the methods/functions available in math module. However, it will be good for you if you try to run them and understand how they work.

A direct answer to this question will solve part b of Assignment2. Therefore, I am providing a rather obvious hint here.
When you say
>>>name = raw_input('What is your name?')

Python will assign whatever the user enters in the variable "name". if in the next line you say
>>>print name
you will see whatever the user typed. This is what you should use to access user's input.

The error in the above code is because of the type of values being used with % operator.
Think about this: 3%2 = 1, what is "three" % 2?
When we use % operator with strings it works as a format string, similar to a %2.2f in a print statement.

The correct way to get the desired output would be a loop like this:

for i in l:
if l.index(i) % 2 == 0: print i

In this, instead of checking whether that item is odd or not we check if the index of that item is odd or not.

First of all, if you want to put code with indentation put it inside pre tag, like this
<"pre"> <-- without quotes
my code line 1
my code line 2
...
<"/pre"> <-- without quotes
After this you need to select "Input Format" (right below the box you are typing this text in) and set it to Full HTML. That way you can display text with indentation.

Coming back to the code, the problem is with the split statement. There should be a space character between those quotes. I just checked the code, I saw that when we call this function (refer Qn 4 of sample midterm, after this function) the string looks like
func("1 2 3 4"), therefore to split this argument string into 4 parts we split it on space. So it should have that space character in split. There is one more error in this code, we need to have an additional comma "," after "and" in line
"print (input[0],input[1]), "and",(input[2],input[3])"

You need to find the patterns given in the question. For instance:
1) Only odd values of i gets printed (1,3 and 5)
2) Loop should terminate "break" after i reaches the value 5 or before it reaches 6 for that matter.
3) Value of guess should be 4 when the loop terminates.

With these observations iterate through the code:
iteration 1) guess = 0, i =0 <- initial values. inp[i] that is, inp[0] = 10 that makes if condition false and elif condition true thereby making guess = guess + 2 = 0 + 2 = 2
then it goes to i = i + 1 = 0 + 1 = 1, and finally prints it "Next 1"
iteration 2) guess = 2, i =1 <- initial values. inp[i] that is, inp[1] = 11 that makes if condition true thereby making guess = guess + 1 = 2 + 1= 3
then it goes to i = i + 1 = 1 + 1 = 2, and finally prints it "Next 2", we do not want that so we have to avoid it. for that we need to introduce a new line. Instead of print "Next" , i we will have:
if i % 2 != 0: print "Next " , i

This will make sure only odd values of i get printed

iteration 3) guess = 3, i =2 <- initial values. inp[i] that is, inp[2] = 3 that makes if condition false and elif condition false too, therefore it goes to i = i + 1 = 2 + 1 = 3, and finally prints it "Next 3"

iteration 4) guess = 3, i =3 <- initial values. inp[i] that is, inp[3] = 5 that makes if condition false and elif condition false too, therefore it goes to i = i + 1 = 3 + 1 = 4, and because of the if statement we introduced in iteration 2 nothing gets printed.

iteration 5) guess = 3, i =4 <- initial values. inp[i] that is, inp[4] = 7 that makes if condition false and elif condition false too, therefore it goes to i = i + 1 = 4 + 1 = 5, and finally prints it "Next 5"

iteration 6)guess = 3, i =5 <- initial values. inp[i] that is, inp[5] = 9 that makes if condition false and elif condition false too, therefore it goes to i = i + 1 = 5 + 1 = 6, and because of the if statement we introduced in iteration 2 nothing gets printed.

iteration 7) guess = 3, i =6 <- initial values. inp[i] that is, inp[6] = 11 that makes if condition true and elif condition false , therefore guess = guess + 1 = 3 + 1 =4, then it goes to i = i + 1 = 6 + 1 = 7, and finally prints it "Next 7" but we do not want any value of i > 5 printed. Therefore we need additional condition in the line we replaced earlier:
if (i%2 !=0) and (i<=5):print "Next ",i
At this point guess becomes 4, which is when our loop should print guess and terminate.

So we add this line too:
if guess == 4: break

In short, the final code will look like this:

guess=0
inp=[10,11,3,5,7,9,11,120]  
i=0
  
   while True:
             if inp[i]>10: guess+=1
             elif inp[i]==10: guess+=2    
             i+=1
             # print “Next ”,i <- replaced 
             if (i%2 !=0) and (i<=5):print "Next ",i
             if guess == 4: break: 
   print guess

              Output:    
              Next 1
              Next 3
              Next 5
              4

I will try to mark font sizes for this exam.